SOLUTION: Marina leaves home at 9AM, bicycling at a rate at 24 mi/h. Two hours later, John leaves driving at the rate of 48 mi/h. At what time will John catch up with Marina?

Question 114675: Marina leaves home at 9AM, bicycling at a rate at 24 mi/h. Two hours later, John leaves driving at the rate of 48 mi/h. At what time will John catch up with Marina?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Marina leaves home at 9AM, bicycling at a rate at 24 mi/h. Two hours later, John leaves driving at the rate of 48 mi/h. At what time will John catch up with Marina?
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Marina DATA:
Rate = 24 mph ; Time = x hrs ; Distance = rt = 24x miles
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John DATA:
Rate = 48 mph ; Time = x-2 hrs ; Distance = rt = 48(x-2) miles
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EQUATION:
distance = distance
24x = 48(x-2)
x = 2(x-2)
x = 4 hrs (Marina's Time)
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9AM + 4 hrs = 1PM
======================
Cheers,
Stan H.

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