SOLUTION: Ana is 24 years older than twice the age of her younger sister. In ten years, their combined ages will be 110 years. How old are they now?

Question 113877: Ana is 24 years older than twice the age of her younger sister. In ten years, their combined ages will be 110 years. How old are they now?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Write an expression/equation for what it says:
:
Ana is 24 years older than twice the age of her younger sister.
A = 2S + 24
:
In ten years, their ages:
(A + 10)
and
(S+10)
:
In 10 years their combined ages will be 110 years.
(A+10) + (S+10) = 110
A + 10 = 110 - S - 10
A = 110 - S - 10 - 10
A = 90 - S
:
(How old are they now?
From the 1st equation, substitute (2S+24)for A in the above equation:
2S + 24 = 90 - S
2s + S = 90 - 24
3s = 66
S = 66/3
S = 22 yrs is the sisters age
:
A = 2S + 24
A = 2(22) + 24
A = 44 + 24
A = 68 yrs is Ana's age
:
Check solution using the statement:
"In ten years, their combined ages will be 110 years"
(68 + 10) + (22 + 10) = 110
:
Could follow this OK? Any questions?
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