SOLUTION: solve for x. 6^(3x-4) 2^(2x+3)=648(48)^x

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Question 1134204: solve for x. 6^(3x-4) 2^(2x+3)=648(48)^x
Found 2 solutions by Edwin McCravy, greenestamps:
Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!


Take logs of both sides  (can take natural logs instead if preferred)



Use the product-to-sum log fact on both sides:



Use the exponent-to-multiplier log fact on both sides:



Let's break three of those logs down to the side:

     1.  

     2. 

     3.  

Those are all in terms of log(2) and Log(3). 

To keep from getting bogged down with too many complicated symbols,

let A = log(2) and let B = log(3), then

     1.  

     2. 

     3.  


Now go back to the equation:



and substitute the expressions in A and B for the logs:



Multiply out:





Combine like terms on the left:



Get all the terms in x on the left and all the others on the right:



Combine like terms:



Factor out x on the left side and 4 out of the right side:



Divide both sides by (A+2B)



Edwin

Answer by greenestamps(13198)   (Show Source): You can put this solution on YOUR website!


The solution using logarithms is valid, but far more work than is needed.

Solve the problem by putting everything in terms of prime factors.






Equate the exponents of each prime factor:

--> x = 4

and

--> x = 4


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