SOLUTION: show that 2x^2+p=2(x-1) has no real roots if p>-3/2

SOLUTION: show that 2x^2+p=2(x-1) has no real roots if p>-3/2

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Question 1133428: show that 2x^2+p=2(x-1) has no real roots if p>-3/2
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The discriminant is when the equation is

Your equation:

--------------------
The discriminant is:

If the discriminant is negative, there are
no real roots

( reverse the inequality sign when dividing by negative )
for no real roots
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