SOLUTION: 1. 3/4x-(x-5)/3=x/2
2. t-12/5+3t/4=(t-6)/2
solve for X
3. x+a/3=c
4. ax+b=cx
5. 3ax-b=d-4cx
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Question 112988: 1. 3/4x-(x-5)/3=x/2
2. t-12/5+3t/4=(t-6)/2
solve for X
3. x+a/3=c
4. ax+b=cx
5. 3ax-b=d-4cx
Answer by veronica0626(5) (Show Source): You can put this solution on YOUR website!
1.
first get the LCD of 3 and 4x, which is 12x.
divide 12x by the denominator 4x you get a 3.
multiply to the numerator 3.
do the same thing with the second term.
multiply and you will get
cross multiply
(equate the product of 12x and x
with the product of (9-4x^2+20x) and 2)
transpose everything to the left side and you get
divide the left side by 2 and you get
use the formula
by substituting a=10, b=20, and c =9
finding the lowest term we have
2.
get the LCD and find the new numerator
multiply and simplify
cross multiply
divide both side by two and we get
combine like terms and we get
then we have
solve for X
(in terms of a nd c)
3.
cross multiply and equate
subtract a to both side of the equation and u get
4.
subtract b+cx on both side and we get
rewrite ax-cx
divide (a-c) on both side and we get
5. 3ax-b=d-4cx
add on both side and we get
rewrite (3ax+4cx)
divide both side by (3a+4c)
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