SOLUTION: write the equation of a line through (-p, q) that is parallel to the line 3x-4y= 5

Question 112963: write the equation of a line through (-p, q) that is parallel to the line 3x-4y= 5
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First find the slope of 3x-4y= 5

Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)

Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)

Start with the given equation

Subtract 3x from both sides

Simplify

Divide both sides by -4 to isolate y

Break up the fraction on the right hand side

Reduce and simplify

The original equation (standard form) is equivalent to (slope-intercept form)

The equation is in the form where is the slope and is the y intercept.

So the slope of 3x-4y= 5 is

If you want to find the equation of line with a given a slope of which goes through the point (-p, q), you can simply use the point-slope formula to find the equation:

---Point-Slope Formula---
where is the slope, and

is the given point

So lets use the Point-Slope Formula to find the equation of the line

Plug in , , and (these values are given)

Distribute

Multiply and to get

Add q to both sides to isolate y

So the equation parallel to 3x-4y= 5 and goes through (-p, q) is
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