SOLUTION: If (√3 - 1) is a root of the equation 2x^2-2kx+4 = 0, then k equals... A)2√3-1 B)√3-2 C)2√3 D)√3 E)√3-1

Algebra.Com
Question 1128329: If (√3 - 1) is a root of the equation 2x^2-2kx+4 = 0, then k equals...
A)2√3-1 B)√3-2 C)2√3 D)√3 E)√3-1

Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.
The equation

    2x^2 - 2kx + 4 = 0 

is equivalent to  (after dividing both sides by 2)


    x^2 - kx + 2 = 0.      (1)


We are given that    is the root of the original equation; hence, the equation (1) with the leading coefficient 1 has this root, too.


Then, applying the Vieta's theorem, the other root of the equation (1) is


     = . =  =  = .


Thus we know BOTH ROOTS of the equation (1) (even without solving it explicitly (!) ). They are


      and  .


Again, according to Vieta's theorem, the sum of these roots is the coefficient at x in equation (1) taken with the opposite sign:


    k =  +  = .


Answer.  k = .

Solved.   //   Option C).



RELATED QUESTIONS

PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME. √(2)[√(4y) - √(18)]... (answered by stanbon)
What is the value of j in the equation √ j + √ j + 14 = 3√ j +... (answered by srinivas.g,MathLover1)
√(2x+1)+√(x-3)=2 (answered by stanbon,MathTherapy,ikleyn)
i have a few questions... 1. find the value of x 2√x+5= √x+45 a. 1 ; (answered by Alan3354)
√x-3 = √x+2 -... (answered by ankor@dixie-net.com)
∫e^√x / √x dx= (A) 2e^√x+C (B) 1/2e^√x+C (C)... (answered by Alan3354)
If (√3 -1) is a root of the equation (2x^2)-2kx+4=0 then k equals: A) 2 √3 -1 B)... (answered by Solver92311)
Simplify... (answered by stanbon)
Solve: 2√(1-x) - 3√(2x-1) =... (answered by josgarithmetic)
√(a -... (answered by lwsshak3)