SOLUTION: Find the values of b such that the equation below always gives real solutions. -3x^2 + bx -1 = 0

Question 1127899: Find the values of b such that the equation below always gives real solutions.
-3x^2 + bx -1 = 0
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.

To satisfy the problem's requirement, the discriminant of the equation must be non-negative:


 >= 0,


 >= 0,


 >= 0,


 >= 12  ====>   b >=  =    OR   b <= - = .


Answer.  The necessary and sufficient condition for "b"  is  |b| >=  =~ 3.464102 .

Solved.

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