SOLUTION: A projectile is fired upward from the ground with an initial velocity of 295 feet per second. Neglecting air resistance (this just means we are keeping it simple), the height of t
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Question 1124535: A projectile is fired upward from the ground with an initial velocity of 295 feet per second. Neglecting air resistance (this just means we are keeping it simple), the height of the projectile at any time, t in seconds, can be described by the following polynomial:
-16t^2+295t
A) How high in the air is the projectile after 7 seconds?
B) Approximate (to the nearest second) how long before the projectile hits the ground. (HINT: What will the height be when the projectile hits the ground?) Do not calculate the exact answer!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ -16t^2\ +\ 295t)
This function provides the height of a projectile in feet at 
seconds after the projectile was fired from an initial height of zero feet at an initial velocity of 295 feet per second.
A) Evaluate )
B) Set \ =\ 0)
and solve for the positive value of
John
My calculator said it, I believe it, that settles it
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