# SOLUTION: I could really use help with this word problem:Stan invested \$13000, part at 17% and part at 2%. If the total interest at the end of the year is \$1,910 how much did he invest at 17

Algebra ->  Algebra  -> Equations -> SOLUTION: I could really use help with this word problem:Stan invested \$13000, part at 17% and part at 2%. If the total interest at the end of the year is \$1,910 how much did he invest at 17      Log On

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 Click here to see ALL problems on Equations Question 112218This question is from textbook Beginning Algebra : I could really use help with this word problem:Stan invested \$13000, part at 17% and part at 2%. If the total interest at the end of the year is \$1,910 how much did he invest at 17%?This question is from textbook Beginning Algebra Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!.17X+.02(13,000-X)=1,910 .17X+260-.02X=1,910 .15X=1,910-260 .15X=1,650 X=1,650/.15 X=11,000 IS THE AMOUNT INVESTED @ 17%. 13,000-11,000=2,000 AMOUNT INVESTED @ 2%. PROOF .17*11,000+.02*2,000=1,910 1,870+40=1,910 1,910=1,910