SOLUTION: I made my own problem for fun and am trying to solve it: x^2y + 5 = 17 While I was writing the equation, I decided to myself that x would be equal to 2 and y would be equal t

Algebra ->  Equations -> SOLUTION: I made my own problem for fun and am trying to solve it: x^2y + 5 = 17 While I was writing the equation, I decided to myself that x would be equal to 2 and y would be equal t      Log On


   

Question 1115384: I made my own problem for fun and am trying to solve it:
x^2y + 5 = 17
While I was writing the equation, I decided to myself that x would be equal to 2 and y would be equal to 3. So far, I have:
x^2y + 5 - 5 = 17 - 5
x^2y = 12
x^2y/y = 12/y
Thanks in advance for your assistance.
However, I am unsure what to do next. I have no idea how to prove mathematically that x^2 equals 4 and y equals 3. I’m not even sure if it is possible to do so.
Answer by josgarithmetic(39838) About Me  (Show Source):
You can put this solution on YOUR website!
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I made my own problem for fun and am trying to solve it:
x^2y + 5 = 17
While I was writing the equation, I decided to myself that x would be equal to 2 and y would be equal to 3. So far, I have:
x^2y + 5 - 5 = 17 - 5
x^2y = 12
x^2y/y = 12/y
Thanks in advance for your assistance.
However, I am unsure what to do next. I have no idea how to prove mathematically that x^2 equals 4 and y equals 3. I’m not even sure if it is possible to do so.
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So you gave yourself an equation x%5E2%2Ay%2B5=17 and you picked some values, x=2 and y=3.
This should mean 2%2A2%2A3%2B5=17
12%2B5=17
17=17
Which is true.

You have nothing to solve. Whatever you were trying to solve was done.
You already gave yourself your value for x and your value for y.