SOLUTION: Each day a mining company crushes 18,000 mg of shale-oil rock, some of it 72 L/mg and the rest 150 L/mg of oil. How much of each type of rock is needed to produce 120 L/mg?

Question 1111575: Each day a mining company crushes 18,000 mg of shale-oil rock, some of it 72 L/mg and the rest 150 L/mg of oil. How much of each type of rock is needed to produce 120 L/mg?
Found 2 solutions by josmiceli, ikleyn:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = mg of 72 L/mg rock needed
Let = mg of 150 L/mg rock needed
-----------------------------------------
(1)
(2)
-----------------------------------------
(2)
(2)
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)
--------------------------------

and
(1)
(1)
(1)
-----------------------------------
6,923.08 mg of 72 L/mg rock
11,076.92 mg of 150 L/mg rock
-----------------------------------
check:
(2)
(2)
(2)
(2)
close enough
Definitely get a 2nd opinion on this one

Answer by ikleyn(52921)   (Show Source): You can put this solution on YOUR website!
.
Each day a mining company crushes 18,000 mg of shale-oil rock, some of it 72 L/mg and the rest 150 L/mg of oil.
How much of each type of rock is needed to produce 120 L/mg?
~~~~~~~~~~~~~~~~~~~~

My opinion is that the condition is RUBBISH,

the problem is RUBBISH

and the post is RUBBISH, too.

            Since NOBODY knows what are these units "mg" and "L/mg" to measure the amount of shale-oil rock.

I just expressed my thoughts regarding this text under the link

https://www.algebra.com/algebra/homework/equations/Equations.faq.question.1111568.html

https://www.algebra.com/algebra/homework/equations/Equations.faq.question.1111568.html

            The right place for this post is in the TRASH section, and NOWHERE ELSE.

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