SOLUTION: The length of a rectangle is (12-4x) units. The perimeter of the rectangle is 42-8x+4y units. In Part A, it asks to describe how you can find an expression for the width of the rec

Question 1111381: The length of a rectangle is (12-4x) units. The perimeter of the rectangle is 42-8x+4y units. In Part A, it asks to describe how you can find an expression for the width of the rectangle. In Part B, it asks to write a simplified expression to represent the width, in units, of the rectangle.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is (12-4x) units. The perimeter of the rectangle is 42-8x+4y units. In Part A, it asks to describe how you can find an expression for the width of the rectangle.
Perimeter:: 42-8x+4y = 2(Length + Width)
42-8x+4y = 2(12-4x + Width)
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21-4x+2y = 12-4x + Width
Width = 9+2y
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In Part B, it asks to write a simplified expression to represent the width, in units, of the rectangle.
Width = 9+2y
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Cheers,
Stan H.
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