SOLUTION: 1.) 3x/(x+1) + 6/2x = 7/x 2.) 6x/(x+4) + 4 = 2x+2/(x-1) 3.) 7x+1/2x+5 + 1 =10x-3/3x 4.) 10/x^2-2x + 4/x = 5/x-2

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Question 110992: 1.) 3x/(x+1) + 6/2x = 7/x
2.) 6x/(x+4) + 4 = 2x+2/(x-1)
3.) 7x+1/2x+5 + 1 =10x-3/3x
4.) 10/x^2-2x + 4/x = 5/x-2

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
1.) 3x/(x+1) + 6/2x = 7/x
x(x+1) is the LCM
Multiply thru by the LCM:
3x^2 + 3(x+1) = 7(x+1)
3x^2 + 3x+3 = 7x+7
3x^2-4x-3=0
x = [4 +- sqrt(16-4*3*-3)]/6
x = [4 +- sqrt(52)]/6
x = [4 +- 2sqrt(13)]/6
x = [2 +- sqrt(13)]/3
x = (2 + sqrt(13))/3 or x = (2 - sqrt(13))/3
==========================
2.) 6x/(x+4) + 4 = (2x+2)/(x-1)
Multiply thru by (x+4)(x-1) to get:
6x(x-1) + 4(x+4)(x-1) = 2(x+1)(x+4)
6x^2-6x + 4x^2+12x-16 = 2x^2+10x+8
8x^2 -4x -24 = 0
4(2x^2 -x -12) = 0
2x^2 - x -12 = 0
x = [1 +- sqrt(1 -4*2*-12)]/4
x = [1 +- sqrt(97)]/4
x = (1+ sqrt(97))/4 or x = (1-sqrt(97))/4
===============
Cheers,
Stan H.

3.) 7x+1/2x+5 + 1 =10x-3/3x
4.) 10/x^2-2x + 4/x = 5/x-2

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