SOLUTION: Solve for x. x^x=1 (Two answers are required) According to math_helper (887), he/she said the following: x^x=1 xXIn(x)=In(1) xXIn(x)=0 Now, here comes the trouble, BUT if I p

Question 1107037: Solve for x.
x^x=1 (Two answers are required)
According to math_helper (887), he/she said the following:
x^x=1
xXIn(x)=In(1)
xXIn(x)=0
Now, here comes the trouble, BUT if I plug in, 0 and 1 are valid,
as 0^0=1, 1^1=1.
But, if I use his/her way:
Predict x=0
0XIn(0)=0
Error=0
???Not valid?
Predict x=1
1XIn(1)=0
0=0
Valid.
So 0 is not valid for x? If not, what's the process to find/prove out x=0?
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
The function of logarithm   IS NOT DEFINED   at x= 0.

Therefore, your device says what it says.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
0^0 = 1 by agreement.
There's no proof, just discussion.
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