SOLUTION: A, B, C, and D are distinct digits, and 4xAAB=CDA. If C is less than D, find the sum A+B+C+D.

Question 1106586: A, B, C, and D are distinct digits, and 4xAAB=CDA. If C is less than D, find the sum A+B+C+D.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

I'll let you solve the problem; I will just show you the way....

(1) The 3-digit number AAB, multiplied by 4, results in the 3-digit number CDA. What is the largest possible value for letter A?

(2) In the ones column, 4 times B produces letter A, so A must be even.

Now you should know the value of letter A.

(3) Again in the ones column, B multiplied by 4 produces letter A; that gives you two possible values for letter B. Try each one; the requirement that C be less than D finishes the solution.
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