SOLUTION: THE AMOUNT OF RADIOACTIVE SUBSTANCE PRESENT, IN POUNDS, AT TIME T, IN DAYS IS GIVEN BY THE FORMULA Y=60(2)^0.2T FIND THE NUMBER OF POUNDS PRESENT IN 30 DAYS

Question 1102662: THE AMOUNT OF RADIOACTIVE SUBSTANCE PRESENT, IN POUNDS, AT TIME T, IN DAYS IS GIVEN BY THE FORMULA Y=60(2)^0.2T FIND THE NUMBER OF POUNDS PRESENT IN 30 DAYS
Found 3 solutions by Boreal, greenestamps, josgarithmetic:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
want 60(2^(0.2t)) which for t=30, 0.2t=6, so it is 60*2^6=60*64=3840 pounds

Answer by greenestamps(13198)   (Show Source): You can put this solution on YOUR website!

The problem is nonsense.

Radioactive decay is represented by an exponential decay function -- not an exponential growth function.

Is the formula supposed to have an exponent of -0.2T, instead of the 0.2T that you show?

And if you want a specific answer as to how much remains after 30 days, you need to tell us how much we started with....
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
Your model is using 60 units or pounds for a starting quantity, and ASSUMING you forgot to include the NEGATIVE SIGN in your exponent expression, the model should be . No usually any reason for using all upper case letters including the variables, unless you have some specific purpose for distinguishing between upper and lower cases.

Let t=30, and solve for y.

or , or fifteen ounces
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