SOLUTION: The sum of three numbers is 119. The second number is 4 times the third. The third number is 7 more than the first. What are the numbers?

Algebra.Com
Question 1100905: The sum of three numbers is 119. The second number is 4 times the third. The third number is 7 more than the first. What are the numbers?
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Let x = the first number
The third number is 7 more than the first.
So the third number = x+7
The second number is 4 times the third.
So the second number = 4(x+7)
The sum of three numbers is 119.
So x + x+7 + 4(x+7) = 118. 

Solve that for x.  It will be the first number
Add 7 to get the third number.  Then multiply
that by 4 to get the second number.

Edwin
RELATED QUESTIONS

The sum of three numbers is 119. The first number is 5 more than the third. The second... (answered by lwsshak3)
The sum of three numbers is 131 . The second number is 4 times the third. The third... (answered by rfer)
The sum of three numbers is 119. The second number is 8 less than the first, and the... (answered by CubeyThePenguin)
The sum of three numbers is 92. The second number is 10 more than the first. The third... (answered by josgarithmetic)
The sum of three numbers is 144. The second number is 6 more than the first . The third... (answered by CubeyThePenguin)
The sum of three numbers is 121. The third number is 4 times the first. The first number... (answered by Edwin McCravy,tajar)
The sum of three numbers is 129 . The third number is 4 times the first. The first (answered by MathLover1)
the sum of three numbers is 66. the third number is 9 more than the first. the second... (answered by timvanswearingen)
The sum of three numbers is 74. The first number is 10 more than the third. The second... (answered by josgarithmetic)