SOLUTION: 4x^2-5x=0

Question 1096409: 4x^2-5x=0
Found 2 solutions by addingup, MathTherapy:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
4x^2-5x=0
this equation is in standard form, ax^2+bx+c = 0, though in this particular equation c = 0, like this:
4x^2-5x+0 = 0
So we solve it right away using the quadratic formula, first + and then -:
(-b+-sqrt(b^2-4ac)/2a
x = (-(-5)+sqrt(-5)^2)/2*4
x = (5+(sqrt25))/8
x = (5+5)/8
x = 10/8
x = 5/4
Now for -:
x = (-(-5)-(sqrt(-5)^2)/2*4
x = 5-5/8
x = 0/8 = 0

Answer by MathTherapy(10551) (Show Source): You can put this solution on YOUR website!

4x^2-5x=0

x(4x - 5) = 0 ------- Factoring out GCF, x
OR
That's it....nothing COMPLEX or CONFUSING!
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