SOLUTION: Find an equation of the line satisfying the given conditions. Through(-3,9),perpendicular to 2x+3y=21

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Question 1095985: Find an equation of the line satisfying the given conditions.
Through(-3,9),perpendicular to 2x+3y=21
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
slope of 2x+3y=21
3y=-2x+21
y=(-2x/3)+7; slope is -2/3
perpendicular line has a slope that is the negative reciprocal, or in this instance 3/2
It goes through (-3, 9)
point slope formula
y-y1=m(x-x1), m is slope, (x1, y1) point
y-9=(3/2)(x+3), watch signs.
y=(3/2)x+9/2+9
y=(3x/2)+27/2
Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

Find an equation of the line satisfying the given conditions.
Through(-3,9),perpendicular to 2x+3y=21
2x + 3y = 21 

3x + 2y = c -------- Switching coefficients on variables, and changing the constant to c

3x - 2y = c -------- NEGATING coefficient on y

3x - 2y = 3(- 3) - 2(9) -------- Substituting GIVEN point (- 3, 9) to determine c

3x - 2y = - 9 - 18

 ---- Required equation 

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