SOLUTION: two angles of a triangle have the same measure and the third one is 57 degrees greater than the measure of each of the other two. find the measure of the largest triangle.

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Question 1093551: two angles of a triangle have the same measure and the third one is 57 degrees greater than the measure of each of the other two. find the measure of the largest triangle.
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
two angles of a triangle have the same measure and the third one is 57 degrees greater than the measure of each of the other two. find the measure of the largest triangle.
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A + A + 57 = 180
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
two angles of a triangle have the same measure and the third one is 57 degrees greater than the measure of each of the other two.
find the measure of the largest angle.
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A + A + (A+57) = 180  ====>

3A + 57 = 180  ====>  3A = 180 - 57 = 123 degrees.


Can you complete from this point ?


See the lesson
    - Solved problems on angles of a triangle
    - Solved problems on angles of a parallelogram
    - Solved problems on angles of a quadrilateral
    - Solved problems on angles of a polygon
    - Solved problems on missed angle of a polygon
    - Solved problems on angles of a regular polygon
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