SOLUTION: Write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. Part B. Keeping the restrictions in mind, solve the equation.
Algebra ->
Equations
-> SOLUTION: Write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. Part B. Keeping the restrictions in mind, solve the equation.
Log On
Question 1089527: Write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. Part B. Keeping the restrictions in mind, solve the equation.
A. 1/x-4 - 5/x+2 = 6/x^2-2x-8
B. 5/x = 10/3x + 4 Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. Part B. Keeping the restrictions in mind, solve the equation.
A.
Factor
multiply by (x-4)(x+2), cancel the denominators and we have
(x+2) - 5(x-4) = 6
x + 2 - 5x + 20 = 6
-4x + 22 = 6
-4x = 6 - 22
-4x = -16
x = -16/-4
x = +4, makes the denominator 0 in the first and last fractions
:
B.
Cross multiply
5(3x+4) = 10x
15x + 20 = 10x
15x - 10x = -20
5x = -20
x = -20/5
x =-4