SOLUTION: [7/3�{4/3+(4/3�16/5-16/5)}�9/5]

Question 1089498: [7/3�{4/3+(4/3�16/5-16/5)}�9/5]
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
I would write it as
7/3�[4/3+(4/3�16/5-16/5)]�9/5
because the outside parentheses are not needed,
and in 7th grade they taught me that
the innermost parenthesis are curvy ones,
the set around them is square parentheses,
and the next one is the curly ones.
Because I see slashes and division signs,
I would read 4/3�16/5 as ,
but it would mean the same if I read it as 4�3�16�5 .

I see to ways to calculate that.

THE JUST CALCULATE WAY:
(I will keep using the symbols � and � until it gets impractical)
7/3�[4/3+(4/3�16/5-16/5)]�9/5=
7/3�[4/3+(64/15-16/5)]�9/5=
7/3�[4/3+(64/15-48/15)]�9/5=
7/3�(4/3+16/15)�9/5=
7/3�(20/15+16/15)�9/5=
7/3�(36/15)�9/5=
7/3�(15/36)�9/5=
=
=
=
=
I could have multiplied to get
and then tried to simplify,
but I prefer to simplify early and often.
It is easier (at least for me).

APPLYING THE DISTRIBUTIVE PROPERTY:

RELATED QUESTIONS
1, 3/4, 5/9,... (answered by ewatrrr)

evaluate {3(7 - 9) + 16}^3 � (-5) -... (answered by Alan3354)

1. {3(7 - 9) + 16}^3 � (-5) -... (answered by Alan3354)

5... (answered by checkley77)

-3(x+4)-5(x-4) 9/16-3/8+1/4... (answered by rfer)

3(-9n + 5) + -4 =... (answered by jessica43)

16/4 + {5*6 -... (answered by solver91311)

-|-9|-|4|-3|5-7| (answered by Edwin McCravy)

(1+2+3+4+5+6+7+8+9+12+14+16+18+19)(0)=? (answered by JBarnum)