SOLUTION: x² + 2y² - 4x + 6y - 5 = 0,
x + y + 5 = 0
Solve by method of substitution. Thank you.
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Question 1080928: x² + 2y² - 4x + 6y - 5 = 0,
x + y + 5 = 0
Solve by method of substitution. Thank you.
Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Substituting,
This equation has no real solutions.
So there is no solution to the system.
.
.
.
Verified by the graph since there is no intersection.
.
.
.
.
Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website!
.
See the lesson
- Solving the system of algebraic equations of degree 2 and degree 1,
in this site. You will find there a lot of similar solved problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Systems of equations that are not linear".
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