Let's draw an arbitrary line through (-3,2) that crosses the
y-axis at (0,b), where "b" is the y-intercept, and the x-axis
at (a,0) where "a" is the x-intercept.



Using the distance formula on (0,b) and (a,0) we find that
the slope is 



Since we are told that the y-intercept "b" is two-thirds of the
x-intercept "a", we can write



So the slope is 

We use the point slope formula to find the equation
of the line through the point (-3,2) with slope :











So the line goes through the origin and has this graph:


So we see that the x-intercept and the y-intercept are both zero,
and they coincide at the origin (0,0).  And, surprisingly, that's 
correct, since two-thirds of zero is indeed zero!  :)

Answer:  

Edwin