SOLUTION: Please help me solve this equation:
1. Determine dy/dx for y = x√x(5x^2 − 3)^4
(There is no need to simplify the answer.)
2. For the curve defined by the equation
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Question 1078501: Please help me solve this equation:
1. Determine dy/dx for y = x√x(5x^2 − 3)^4
(There is no need to simplify the answer.)
2. For the curve defined by the equation x^2 − xy + y^2 = 3
(a) Show that
dy/dx =2x − y/x − 2y
(b) Find the equation of the normal to the curve at the point (−1, 1).
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
where and
So then,
So then,
.
.
.
2a. Differentiate implicitly,
.
.
.
2b. The slope of the tangent line is equal to the value of the derivative at the point.
The tangent and normal line are perpendicular to each other so their slopes are negative reciprocals.
So then using the point-slope form of a line,
.
.
.
.
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