SOLUTION: Simplify: (a^2-8a)/(2a^2+5a-3)*(2a-1)/(a^2+2a+4)*(a+3)/(a^2-2a)

Algebra.Com
Question 1077452: Simplify: (a^2-8a)/(2a^2+5a-3)*(2a-1)/(a^2+2a+4)*(a+3)/(a^2-2a)
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!


Write as a division:



Invert the second fraction and change division to multiplication



Factor a²-8a by taking out common factor "a", getting a(a-8).
Factor 2a²+5a-3 as (2a-1)(a+3).
Factor a²-2a by taking out common factor "a", getting a(a-2).
Note that a²+2a+4 does not factor.



There are two (2a-1) factors in the first denominator so write (2a-1)²



Nothing cancels, so we can only multiply the numerators and denominators,
and write the (a+3)(a+3) as (a+3)² 



Edwin
RELATED QUESTIONS

2-3(a-4)=2a (answered by jim_thompson5910)
2a^2+5a-3 all over a+2 times 9a+18 all over 1-2a (answered by stanbon)
Simplify 2a^-2/... (answered by Boreal,Theo)
2a^2 +... (answered by TigerAlgebra)
Simplify: a + 5a +... (answered by Nihat Routsong)
(a-2)(a+4)=... (answered by checkley75)
Please help me solve : subtract 5a^2-2a-1 from... (answered by josgarithmetic)
Simplify 1) a+5a+2a 2)(-6a)(4b) 3)5.7xy-1.2xy 4)-10(2a-6b)... (answered by ikleyn)
solve 2a+(2/3)=a-(1/3) (answered by jim_thompson5910)