SOLUTION: x+7/7x+5 ÷ x-8/x^2-3x-40
Algebra.Com
Question 1070177: x+7/7x+5 ÷ x-8/x^2-3x-40
Found 2 solutions by Alan3354, Boreal:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Not clear, add parentheses.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x+7/7x+5 ÷ x-8/x^2-3x-40
The quadratic factors into (x-8)(x+5), so the x-8 cancels and the divisor is 1/(x+5)
invert and multiply.
(x+7)(x+5)/(7x+5). The (x+5) and the 7x+5 cannot cancel.
RELATED QUESTIONS
-7x+4=-x-8+5(2-3x) (answered by unlockmath)
multiply
(x+5)(3x-8)
A 3x^2-40x+7
b x^2+7x+7
c 3x^27x-40
d 3x^2+6x-40
^ means to (answered by jim_thompson5910)
7-7x=(3x+2)(x-1) (answered by Fombitz)
may you please help me sovle these problems?
8x^2 - 6x - 7 divide 4x + 3
3x^2 - x - (answered by ikdeep)
simplify:... (answered by Jessmh123)
Perform the operations indicated:
1. (7x- 2) + (6x+ 4)
2. (3x - 3.5) - (x + 1.8)
3.... (answered by rfer)
Perform the operations indicated:
1. (7x- 2) + (6x+ 4)
2. (3x - 3.5) - (x + 1.8)
3.... (answered by solver91311)
x^2=7x+7 (answered by tommyt3rd)
2=x-7x+8 (answered by oscargut)