SOLUTION: I have an assignment what's due Monday and the question says, Solve the following equation: {{{ 4^(x+1) = 16^x }}}
I know you have to do something about letting them both have
Question 1069001: I have an assignment what's due Monday and the question says, Solve the following equation:
I know you have to do something about letting them both have the same base, but I don't know what to do after that.
Please Help and Thank you! Found 2 solutions by Boreal, ikleyn:Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website! Write both of them to the same base, 2 or 4, 4 is easier
4^(x+1)=(4^2)^x=4^2x
now you have the same base, so you can set the exponents equal to each other.
x+1=2x
x=1
4^2=16^1 Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website! .
Let us write the right side in the base 4:
= = .
Now the equation takes the form
= .
It implies
x + 1 = 2x ---> x = 1.
Answer. x = 1.
Check. Left side is = = 16.
Right side of the original equation is = = 16.
Checked.