SOLUTION: The length of a rectangle is 44 inches greater than twice the width. If the diagonal is 2 inches more than the�length, find the dimensions Length 2w+44 Diagonal 2w+46

Question 1067641: The length of a rectangle is
44
inches
greater
than twice the width. If the diagonal is 2 inches more than the�length, find the dimensions
Length 2w+44
Diagonal 2w+46
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
The length and with are the legs of a triangle,
and the diagonal is the hypotenuse.
So
subtract from each side.

factoring,

So w = -10 or w = 18
Since we need a positive width, w = 18
The length is 2w+44 = 2(18) + 44 = 36 + 44 = 80
The diagonal is 2w + 46 = 2(18) + 46 = 36 + 46 = 82
Notice that 18^2 + 80^2 = 82^2
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