SOLUTION: The equation 2x^2-5x=-12 is rewritten in the form of 2(x-p)^2+q=0. What is the value of q?

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Question 1065310: The equation 2x^2-5x=-12 is rewritten in the form of 2(x-p)^2+q=0. What is the value of q?
Found 3 solutions by josgarithmetic, josmiceli, Edwin McCravy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!



The form containing p,




Comparing the corresponding coefficients,

Can you continue here and solve this system and find the value for q?
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!



-----------------------------------
The given equation is:


------------------------------



------------------







-------------------------
check:







OK

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
The equation 2x^2-5x=-12 is rewritten in the form of 2(x-p)^2+q=0. 



So we have the identity



Substitute x = 0





Substitute x=p





Equate the two expressions for q

 ≡ 

 ≡ 

 ≡ 

 or 
             

But p cannot be 0, since

 ≡ 

 ≡  cannot be an identity, since 
there is no x term on the left







So (p,q) = 

But the first

Edwin
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