SOLUTION: Using physics, it can be shown that if a ball is thrown upwards with an initial velocity
of 16 ft/s from the top of a building 64 ft high, then its height h above the ground t
se
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Question 1065243: Using physics, it can be shown that if a ball is thrown upwards with an initial velocity
of 16 ft/s from the top of a building 64 ft high, then its height h above the ground t
seconds later will be
h(t) = 64 + 16t − 16t2
During what time interval will the ball be at least 32 ft above the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h(t) = 64 + 16t − 16t2
During what time interval will the ball be at least 32 ft above the ground?
----
h(t) = 64 + 16t - 16t^2 = 32
Solve for t
You'll get 2 values, 1 ascending, 1 descending.
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