SOLUTION: Please help find the values of A and B: A-B=1 and 2A^2+20=B^3

Question 1063061: Please help find the values of A and B:
A-B=1 and 2A^2+20=B^3
Found 2 solutions by Fombitz, rothauserc:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

So,

and

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Graph the B function to find where it has a zero.
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so then,

Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
A - B = 1
:
1) A = B + 1
:
2) 2A^2 + 20 = B^3
:
substitute for A in equation 2 using equation 1
:
2(B+1)^2 + 20 = B^3
:
2(B^2+2B+1) + 20 = B^3
:
2B^2 +4B +2 + 20 = B^3
:
B^3 -2B^2 -4B -22 = 0
:
a graph of this equation will help
:

:
B is approximately 4.2
:
*********************
A is 5.2 and B is 4.2
*********************
:

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