SOLUTION: FIND 3 CONSECUTIVE ODD INTEGERS SUCH THAT THE PRODUCT OF THE FIRST AND THIRD EXCEEDS THE SECOND BY 38. SHOW WORK- PLEASE HELP!

Question 106165: FIND 3 CONSECUTIVE ODD INTEGERS SUCH THAT THE PRODUCT OF THE FIRST AND THIRD EXCEEDS THE SECOND BY 38.
SHOW WORK- PLEASE HELP!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
FIND 3 CONSECUTIVE ODD INTEGERS SUCH THAT THE PRODUCT OF THE FIRST AND THIRD EXCEEDS THE SECOND BY 38.
------------
Let the integers be x, x+2, x+4
EQUATION:
x(x+4)= x+2+38
x^2+4x = x+40
x^2+3x-40 = 0
(x+8)(x-5) = 0
---
Positive answer:
x = 5
x+2 = 7
x+4 = 9
============
Cheers,
Stan H.
RELATED QUESTIONS
Find 3 consecutive odd integers such that 3 times the product of the first and third... (answered by CubeyThePenguin)

ind three consecutive odd integers such that the product of the first and second exceeds... (answered by drk)

ind three consecutive odd integers such that the product of the first and second exceeds... (answered by nerdybill)

Find three consecutive odd integers such that the product of the first and the second... (answered by jim_thompson5910)

Find four consecutive odd integers such that the product of the second and third exceeds... (answered by mananth)

Find three consecutive odd integers such that the product of the first and the second... (answered by ewatrrr)

Find three consecutive odd interrgers such that the product of the first and the second... (answered by stanbon)

find three consecutive odd integers such that twice the sum of the first and third... (answered by scott8148,ewatrrr)

Find three consecutive negative integers such that 3 times the product of the first and... (answered by stanbon)