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Thomas went to the store and spent half of his money and then $8 more. He went to a second store, spent half
of his remaining money and then $8 more. Given that he had $7 left, how many dollars did he start with?
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I will solve the problem without using equations, by moving from the end to the beginning.
1. In the second store Thomas spent half of his remaining money and then $8 more; after that he had $7 left.
In other words,
"remaining money" - ("half of his remaining money" + $8) = $7.
It implies that
"remaining money" - "half of his remaining money" = $7 + $8 = $15, or
"half of his remaining money" = $15.
It implies, in turn, that "remaining money" = $30.
So, we derived that "remaining money" amount after shopping in the first store was $30.
2. In the first store Thomas spent half of his money and then $8 more; after that he had $30 left (as we just concluded from the step #1).
In other words,
"Total original money" - ("half of the total original money" + $8) = $7.
It implies that
"The total original money" - "half of the total original money" = $30 + $8 = $38, or
"half of the total original money" = $38.
Now, everybody can conclude that "total original money" = two times $38, or $76.
Answer. Thomas started with $76.
Solved.
The solution by "LynnMomo" is wrong.
Thomas went to the store and spent half of his money and then $8 more. He went to a second store, spent half of his remaining money and then $8 more. Given that he had $7 left, how many dollars did he start with?
I'll do the problem from the beginning
Let initial amount he had, be A
After spending half of his money, plus $8 at the 1st store, he had: left
After spending half of the remainder, plus $8 at the 2nd store, he had: left
Since he had $7 left, we get:
A – 48 = 28 ------ Multiplying by LCD, 4
A, or initial amount he had was