SOLUTION: Find the vertex and the axis of symmetry of the parabola:
-4x^2+2x+11=0
Algebra.Com
Question 1060540: Find the vertex and the axis of symmetry of the parabola:
-4x^2+2x+11=0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the vertex and the axis of symmetry of the parabola:
f(x) = -4x^2+2x+11=0
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The AOS is x = -b/2a
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Vertex is (x,f(x)), x = -b/2a
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