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A rectangular piece of land has been claimed using a 160 yard cord. If the length of this rectangular lot
is 20 yards more than twice it's width, then what are the dimensions of the lot
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If "w" represents the width, then the length is 2w+20.
The perimeter is (2w+20) + w + (2w+20) + w = 6w + 40.
Hence, the equation is 6w + 40 = 160, ---> 6w = 120 ---> w = {{120/6}}} = 20.
Answer. The width is 20 ft. The length is 2w + 20 = 2*20+20 = 60 ft.
For many other similar solved problems see the lessons
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