SOLUTION: find the point whose distance from (7,-3) is square root of 58 and whose abscissa equals its ordinate. Please show your solution.

Question 1058619: find the point whose distance from (7,-3) is square root of 58 and whose abscissa equals its ordinate. Please show your solution.
Answer by solve_for_x(190) (Show Source): You can put this solution on YOUR website!
Since the abscissa and ordinate of the unknown point are the same, the point
can be represented by (x, x).
The distance from (7, -3) to (x, x) is given by:

Since the distance is equal to √58, we can write:

This gives solutions of x = 0 and x = 4.

Solution: There are two such points: (0, 0) and (4, 4)
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