SOLUTION: log(x-4)+log5=2

Algebra.Com
Question 1055419: log(x-4)+log5=2
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
start with log(x-4) + log(5) = 2
subtract log(5) from both sides of this equation to get log(x-4) = (2 - log(5))
this is true if and only if 10^(2-log(5)) = x - 4
add 4 to both sides of this equation to get 10^(2-log(5)) + 4 = x
simplify to get 10^(1.301029996) + 4 = x
simplify further to get 24 = x

that should be your solution.
evaluate your original equation using x = 24.
log(x-4) + log(5) = 2 becomes log(20) + log(5) = 2
evaluate to get 2 = 2
this confirms the solution is correct.


RELATED QUESTIONS

Log(x-2)+log5=log100 (answered by lwsshak3)
log(2+x)-log(x-2)=log5 (answered by josgarithmetic,ikleyn)
{{{log(x+5)-log(x+2)=log5}}} (answered by jim_thompson5910)
Log(4x)=log5+log(x-4) (answered by lwsshak3)
log5(x-2)= 2 + log5(x-4) (answered by lwsshak3)
log5(X-4)=... (answered by stanbon)
log5(x-1)=4+log5(x-2) (answered by nerdybill)
log5(x-4)=-2 (answered by stanbon)
Solve:... (answered by lwsshak3)