SOLUTION: Mrs Parkson buys some oranges from a supermarket. She finds that: I. If she buys a dozen oranges in brand A, she will have $96 left. II. If she buys two dozen oranges in brand B,

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Question 1054033: Mrs Parkson buys some oranges from a supermarket. She finds that:
I. If she buys a dozen oranges in brand A, she will have $96 left.
II. If she buys two dozen oranges in brand B, she will use half of the money brought.
Given that the price of each orange in brand B is $1 less than that in brand A, find the original amount that Mrs Parkson has.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
x, price of one of brand A
y, price of one of brand B
h, amount of money Mrs. Parkson is holding before any purchase


BUY 12 of brand A, keep $96.



BUY 24 of brand B, keep dollars.

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This makes for a system of equations

and you can probably solve this without trouble.



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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Mrs Parkson buys some oranges from a supermarket. She finds that:
I. If she buys a dozen oranges in brand A, she will have $96 left.
II. If she buys two dozen oranges in brand B, she will use half of the money brought.
Given that the price of each orange in brand B is $1 less than that in brand A, find the original amount that Mrs Parkson has.
Let original amount she had be D

Then cost of 1 dozen Brand A oranges = D – 96, and cost of 1 Brand A orange is: 

Cost of 2 dozen Brand B oranges = ½D, or , & cost of 1 Brand B orange = 

We then get: 

4(D – 96) = D + 48 ------- Multiplying by LCD, 48

4D – 384 = D + 48

4D – D = 48 + 384

3D = 432

D, or original amount she had was:  

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