SOLUTION: A contractor buys 20 yd^2 of nylon carpet and 28 yd^2 of wool carpet for $1300. A second purchase, at the same prices, includes 15 yd^2 of nylon carpet and 20 yd^2 of wool carpet f

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Question 1050456: A contractor buys 20 yd^2 of nylon carpet and 28 yd^2 of wool carpet for $1300. A second purchase, at the same prices, includes 15 yd^2 of nylon carpet and 20 yd^2 of wool carpet for $945. Find the cost per square yard of the wool carpet.
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
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A contractor buys 20 yd^2 of nylon carpet and 28 yd^2 of wool carpet for $1300. A second purchase, at the same prices,
includes 15 yd^2 of nylon carpet and 20 yd^2 of wool carpet for $945. Find the cost per square yard of the wool carpet.
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The condition says:

20*N + 28*W = 1300,    (1)    ("20 yd^2 of nylon carpet and 28 yd^2 of wool carpet for $1300")
15*N + 20*W =  945.    (2)    ("the second purchase . . . )

You have the system of two equations in two unknowns
N is the price for 1 yd^2 nylon carpet
W is the price for 1 yd^2 wool  carpet.

Solve it by any method you know.

There are the lessons
    - Solution of a linear system of two equations in two unknowns by the Substitution method
    - Solution of a linear system of two equations in two unknowns by the Elimination method
    - Solution of a linear system of two equations in two unknowns using determinant
    - Geometric interpretation of a linear system of two equations in two unknowns
    - Solving word problems using linear systems of two equations in two unknowns
in this site that might be interesting to you.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.


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