SOLUTION: A ball is thrown upward with an initial velocity of 64ft/sec from a height 720ft. It's height s, in feet, after t seconds is given by s = -16t^2 + 64t + 720. After how long will th

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Question 1048745: A ball is thrown upward with an initial velocity of 64ft/sec from a height 720ft. It's height s, in feet, after t seconds is given by s = -16t^2 + 64t + 720. After how long will the ball reach the ground? Please show work.
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
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A ball is thrown upward with an initial velocity of 64ft/sec from a height 720ft. It's height s, in feet, after t seconds is given by
s = -16t^2 + 64t + 720. After how long will the ball reach the ground? Please show work.
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