SOLUTION: A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. How many of each coin does the person have?

Algebra.Com
Question 1048612: A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. How many of each coin does the person have?
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Let represent the number of quarters. Then must be the number of dimes. There are cents in quarters. There are cents in dimes. $2.80 is 280 cents.



Solve for then calculate

John

My calculator said it, I believe it, that settles it


RELATED QUESTIONS

A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the... (answered by stanbon)
a person has quarters and dimes that total $2.80. The number of dimes is 7 more than the (answered by checkley77)
Terry has 7 more quarters than dimes and has a total of $6.80. The number of quarters and (answered by fractalier)
Max has $2.15 in dimes and quarters. The number of dimes is 2 more than 4 times the... (answered by lwsshak3)
a boy has 7 more dimes than quarters. The total value of the coins is $4.90. Find the... (answered by josmiceli)
taylor has $3.15 in dimes and quarters. the sum of dimes is 7 more than the number of... (answered by Alan3354)
Peter has been saving his loose change for several days. When he counted his quarters and (answered by ikleyn,greenestamps)
Brandon has a jar of quarters and dimes with a total value of $6.30. The number of... (answered by solver91311,greenestamps)
I have $14.80 in dimes and quarters the number of quarters is 2 less than 3tims the... (answered by Alex2dadeath)