SOLUTION: A square is inscribed in a circle whose equation is x^2+y^2=18. Find the dimension of the square.
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Question 1041863: A square is inscribed in a circle whose equation is x^2+y^2=18. Find the dimension of the square.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A square is inscribed in a circle whose equation is x^2+y^2=18. Find the dimension of the square.
The circle has radius = sqrt(18) = 3sqrt(2)
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The square has diagonal = 2*3sqrt(2) = 6sqrt(2)
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Let each side of the equare be "x"::
x^2 + x^2 = (6sqrt(2))^2
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2x^2 = 72
x^2 = 36
x = side = 6
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Dimensions of the square:: 6 by 6
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Cheers,
Stan H.
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