SOLUTION: a rectangle has a width of x+9 and its width is x+7. Find the dimensions of the rectangle if its area is 143 square meters.
Algebra.Com
Question 1036138: a rectangle has a width of x+9 and its width is x+7. Find the dimensions of the rectangle if its area is 143 square meters.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The area of a rectangle is where A is the area, L is the length and W is the width.
In this case, A = 143, L = x+7 and W = x+9.
Let's plug these expressions in. Then let's solve for x.
or
or
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The possible solutions are or
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If , then
L = x+7 = 4+7 = 11
W = x+9 = 4+9 = 13
So if x = 4, then the rectangle is 13 meters by 11 meters. Notice how 11*13 = 143
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If , then
L = x+7 = -20+7 = -13
W = x+9 = -20+9 = -11
but having negative side lengths doesn't make much sense. So we ignore the solution x = -20
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The only practical solution is x = 4
That leads to the dimensions of the rectangle being 13 meters by 11 meters
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