SOLUTION: In a chemistry class, 8 liters of a 4% silver iodide solution must be mixed with a 10 % solution to get a 6% solution. How many liters of the 10% solution are needed?
A) 5.0 L
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Question 1031892: In a chemistry class, 8 liters of a 4% silver iodide solution must be mixed with a 10 % solution to get a 6% solution. How many liters of the 10% solution are needed?
A) 5.0 L
B) 4.0 L
C) 8.0 L
D) 3.0 L
Could you please tell me step by step how to get the answer.
Found 2 solutions by mananth, stanbon:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
-------------- percent ---------------- Amount
Solution I 4 ---------------- 8 L
Solution II 10 ---------------- x L
Mixture 6 ---------------- 8 + x L
4 * 8 + 10 x = 6 ( 8 + x )
32 + 10 x = 48 + 6 x
10 x -6 x = -32 + 48
4 x = 16
/ 4
x = 4 L Solution II
m.ananth@hotmail.ca
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a chemistry class, 8 liters of a 4% silver iodide solution must be mixed with a 10 % solution to get a 6% solution. How many liters of the 10% solution are needed?
------
Quantity Eq:: 8 + t = s
Iodide Eq:: 0.32 + 0.10t = 0.06s
-----------------------------------------
Substitute for "s" and solve for "t"::
0.32 + 0.10t = 0.06(8 + t)
32 + 10t = 48 + 6t
4t = 16
t = 4 liters (amt. of 10% solution needed)
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Ans: B
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Cheers,
Stan H.
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A) 5.0 L
B) 4.0 L
C) 8.0 L
D) 3.0 L
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