SOLUTION: Jill has $3.50 in nickels and dimes. If she has 50 coins, how
many of each type of coin does she have?
Algebra.Com
Question 102919: Jill has $3.50 in nickels and dimes. If she has 50 coins, how
many of each type of coin does she have?
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
N+D=50 OR N=50-D
5N+10D=350
5(50-D)+10D=350
250-5D+10D=350
5D=350-250
5D=100
D=100/5
D=20 NUMBER OF DIMES.
50-20=30 NUMBER OF NICKLES.
PROOF
5*30+10*20=350
150+200=350
350=350
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