SOLUTION: How to find {{{B^2}}} in {{{1^2 + B^2}}} = {{{(sqrt(2))^2}}} ?

SOLUTION: How to find {{{B^2}}} in {{{1^2 + B^2}}} = {{{(sqrt(2))^2}}} ?

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Question 1025416: How to find in = ?
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
How to find in = ?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 =    --->

 = ,

 = ,

 = .

One more step, and

B = +/-1.

Notice that I edited your post.

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