SOLUTION: A jogger starts from one end of a 12-mile nature trail at 8:00 A.M. One hour later, a cyclist starts from the other end of the trail and rides toward the jogger. If the rate of the

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Question 1024859: A jogger starts from one end of a 12-mile nature trail at 8:00 A.M. One hour later, a cyclist starts from the other end of the trail and rides toward the jogger. If the rate of the jogger is 6 mph and the rate of the cyclist is 12 mph, at what time will the two meet?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
                   rate             time          distance

JOGGER              6               t+1

CYCLIST            12                t

BOTH TOTAL                                         12


The two meet when the sum of their distances traveled becomes 12 miles. 


                   rate             time          distance

JOGGER              6               t+1          6(t+1)

CYCLIST            12                t           12t

BOTH TOTAL                                         12



Solve for t, quantity in hours.
This t is the number of hours past 8:00AM when the jogger and the cyclist meet.



SOLUTION STEPS FOR THE EQUATION




, which is 20 minutes.

They meet at 9:20AM.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
A jogger starts from one end of a 12-mile nature trail at 8:00 A.M. One hour later, a cyclist starts from the other end of the trail and rides toward the jogger. If the rate of the jogger is 6 mph and the rate of the cyclist is 12 mph, at what time will the two meet? 
They meet  hours after the jogger begins or  hour after the cyclist begins, which is:  

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