SOLUTION: Evaluate y' at the point (2,1) if x2 y3 = x + y + 1 2xy^3 + 3x^2y^2y' = 1 + y' 4 + 12y' = 1 + y' 11y' = -3 y' =

Algebra.Com
Question 1023188: Evaluate y' at the point (2,1) if x2 y3 = x + y + 1

2xy^3 + 3x^2y^2y' = 1 + y'
4 + 12y' = 1 + y'
11y' = -3
y' =

Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
Evaluate y' at the point (2,1) if x2 y3 = x + y + 1
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

2xy^3 + 3x^2y^2y' = 1 + y'

4 + 12y' = 1 + y'

11y' = -3

y' = .

You did it correctly.
I only wrote the answer.


RELATED QUESTIONS

implicit differeniation to find y' and evaluate y' at the indicated point . 1) xIn y + (answered by Fombitz)
(4)/(x-7x)-(2y)/(y-2)=-(1)/(2xy+x) (answered by ikleyn)
3y/y²-3y-4 + 3/4-y =... (answered by ikleyn)
Solve the systems using substitution. 1) 3x - 11y = 16 x + y = 3 2) 4x - y... (answered by grishma.kshatriya)
Evaluate the following expressions when x=3, y=-2, and z=-1... (answered by solver91311)
((y^2+y)/(3xy))((3x+3)/(y^2+2y+1))= (answered by ReadingBoosters,MathLover1)
Give the domain of the following functions: 1. 3x + 2y = 7 2. y = x2 3. (answered by sofiyac)
1. 2x-y=1 6x-3y=3 2. y=5x-1 y=5x+4 3. x+y=38 x=2y-25 4. -2x+5y=9 (answered by MathLover1)
-2xy + 2y^2/(x^2 - y^2) + 1/1 tha answer is... (answered by mananth)